方法1:
第一项:a1, 公比:q
a1=a1
a2=a1•q¬
a3=a1•q¬2
a4=a1•q¬3
an=a1•q¬n-1
an+1=a1•qn¬
Sn+1=a1+a1•q¬+a1•q¬2+a1•q¬3+…+a1•q¬n-1+ a1•qn¬
Sn+1=a1+q(a1•q¬+a1•q¬2+a1•q¬3+…+a1•q¬n-1)
Sn+ a1•qn =a1+q•Sn
Sn-q•Sn= a1-a1•qn
Sn= a1•(1- qn)/(1-q)
方法2:
等比数列求和公式推导
(1)Sn=a1+a2+a3+...+an(公比为q)
(2)q*Sn=a1*q+a2*q+a3*q+...+an*q
=a2+a3+a4+...+a(n+1)
(3)Sn-q*Sn=a1-a(n+1)
(4)(1-q)Sn=a1-a1*q^n
(5)Sn=(a1-a1*q^n)/(1-q)
(6)Sn=(a1-an*q)/(1-q)
(7)Sn=a1(1-q^n)/(1-q)
(8)Sn=k*(1-q^n)~y=k*(1-a^x)